Question

Find the magnitude of the centripetal acceleration of a particle on the tip of a fan blade, 0.30 metre in diameter, rotation at 1200 rev/minute

(a) 40 m/s^2

(b) 4737.6 m/s^2

(c) 245 m/s^2

(d) 20 m/s^2

I got this question in a national level competition.

I would like to ask this question from Motion in a Plane in division Laws of Motion of Engineering Physics I

Answer 1

Correct option is (b) 4737.6 m/s^2

To elaborate: v = 1200/60 = 20rps

ω = 2πv = 2×π×20 = 40π rad/sec

Magnitude of acceleration = rω^2 = 0.30×(40π)^2 = 4737.6 m/s^2.