Question

A boy of 50kg is standing in a lift moving down with an acceleration 9.8m/s^2. The apparent weight of the boy is?

(a) Zero

(b) (50×9.8)N

(c) 50N

(d) 50/9.8N

This question was posed to me in an international level competition.

I need to ask this question from Friction and Motion in chapter Laws of Motion of Engineering Physics I

Answer 1

Right choice is (a) Zero

Best explanation: Apparent weight = m(g-a)

Apparent weight = 50(9.8-9.8) = 0.