Question

What is the lattice constant for FCC crystal having atomic radius 1.476 Å?

(a) 1.476 Å

(b) 4.1748 Å

(c) 5.216 Å

(d) 0

I got this question in a national level competition.

The query is from Classification of Solids in division Mechanical Properties of Solids of Engineering Physics I

Answer 1

Right choice is (b) 4.1748 Å

To explain I would say: Radius=1.476 Å or 1.476 × 10^-10 m

Lattice constant for FCC = 4r/√2

Lattice constant = 4.1748 Å.