Question

If 1g of steam is mixed with 1g of ice, what is the resultant temperature of the mixture?

(a) 270°

(b) 230°

(c) 100°

(d) 50°

I got this question during an online interview.

I need to ask this question from Temperature and Specific Heat in section Mechanical Properties of Solids of Engineering Physics I

Answer 1

Correct answer is (c) 100°

The best explanation: Heat required to change 1g of ice at 0°C first into the water at 0°C and then into the water at 100°C,

Q=mL+mc∆T=1×80+1×1×100=180cal

Now 1g of steam carries 540cal of heat when 1g of steam is mixed with 1g of ice, entire steam will not condense. Finally, we will have a mixture of water and steam at 100°C.