Question

A particle executes simple harmonic motion with an amplitude a. The period of oscillation is T. The minimum time taken by the particle to travel half of the amplitude from the equilibrium position is?

(a) T/12

(b) T/8

(c) T/4

(d) T/2

I have been asked this question in examination.

Query is from Oscillatory Motion topic in chapter Oscillations of Engineering Physics I

Answer 1

Correct option is (a) T/12

Easy explanation: y=asinωt

a/2=asin⁡(2π/T)t

sin⁡(2π/T)t=sin⁡(π/6)

2π/T×t=π/6 or t=T/12.