Question

What is the maximum acceleration of the particle executing the simple harmonic motion, y = 2sin[(πt/2)+φ], where y is in cm?

(a) π/2 cm/s^2

(b) π^2/2 cm/s^2

(c) π/4 cm/s^2

(d) π^2/4 cm/s^2

I got this question by my college director while I was bunking the class.

I need to ask this question from Harmonic Motion in chapter Oscillations of Engineering Physics I

Answer 1

Correct choice is (b) π^2/2 cm/s^2

To explain I would say: y=2sin⁡[(πt/2)+]

y=Asin(ωt+φ)

A=2cm,ω=(π/2 rad)/s

amax=ω^2 A=π^2/2 cm/s^2.