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Two simple pendulums of lengths 5m and 20m respectively are given small linear displacement in one direction at the same time. They will again be in the phase when the pendulum of shorter length has completed.

(a) 2 oscillations

(b) 1 oscillation

(c) 5 oscillations

(d) 3 oscillations

The question was asked during an online exam.

This question is from Wave Motion topic in section Waves of Engineering Physics I

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Right option is (b) 1 oscillation

To explain: T1/T2 =√(l1/l2)=√(5/20)=1/2

T1=2T2

When the longer pendulum completes 2 oscillations, the shorter pendulum completes one oscillation and both are again in same phase.

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