Question

Two monatomic ideal gases 1 and 2 of molecular masses M1 and M2 respectively are enclosed in separate containers kept at the same temperature. The ratio of the speed pf spund in gas 1 to that in gas 2 is given by?

(a) √(M1/M2)

(b) √(M2/M1)

(c) M1/M2

(d) M2/M1

I had been asked this question in an internship interview.

Origin of the question is Transverse Waves topic in division Waves of Engineering Physics I

Answer 1

Right option is (b) √(M2/M1)

To elaborate: v=√(3RT/M)

v1/v2 = √(M2/M1).