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A train is approaching with velocity 25m/s towards a pedestrian standing on the track, frequency of horn of train is 1 kHz. Frequency heard by the pedestrian is (v=350m/s).

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A train is approaching with velocity 25m/s towards a pedestrian standing on the track, frequency of horn of train is 1 kHz. Frequency heard by the pedestrian is (v=350m/s).

(a) 1077Hz

(b) 1167Hz

(c) 985Hz

(d) 945Hz

The question was posed to me during an online interview.

My question is taken from Stationary Waves topic in chapter Waves of Engineering Physics I

1 Answer

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Right answer is (a) 1077Hz

The explanation: γ^‘=v/(v-vs)×γ=350/(350-25)×1000Hz

=1077Hz.

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