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A cinema theatre has a volume of 750m^2. What should be the total absorption in the theatre if the reverberation time of 1.5seconds is to be maintained?

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A cinema theatre has a volume of 750m^2. What should be the total absorption in the theatre if the reverberation time of 1.5seconds is to be maintained?

(a) 835 open window units

(b) 1125 open window units

(c) 500 open window units

(d) 750 open window units

I got this question by my school principal while I was bunking the class.

This intriguing question originated from Reverberation in chapter Waves of Engineering Physics I

1 Answer

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Correct answer is (a) 835 open window units

The explanation: Reverberation time = 0.167/Σas

Total absorption Σas = 0.167V/T

Total absorption = 835 open window units.

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