Right choice is (d) 508Hz
Easiest explanation: Let the frequency of tuning fork = v
The fork produces 4 beats/s with a tuning fork of frequency 512Hz
Therefore, v = 512±4 = 516Hz or 508Hz
The fork also produces 6 beats/s with a tuning fork of frequency 514Hz
Therefore, v = 514±6 = 520Hz or 508Hz
508Hz is common in both cases. Therefore, the frequency of the tuning fork is 508Hz.