Correct option is (d) 3.75 Kg
For explanation I would say: E0 = mc^2 = γm1c^2 + γm2c^2
E0 = \(\frac{m1C^2}{\sqrt{1-\frac{v^2}{c^2}}} + \frac{m2C^2}{\sqrt{1-\frac{v^2}{c^2}}}\)
m = E/c^2
Therefore, m = \(\frac{m1+m2}{\sqrt{1-\frac{v^2}{c^2}}}\)
m = 3/0.8
m = 3.75 Kg.