Right option is (b) 4980 Å
Easiest explanation: Work function, Φ0 = hv0 or \(\frac{hc}{λ_0}\)
Therefore, λ0 = \(\frac{hc}{\Phi_0} \)
Here, Φ0 = 2.5 eV = 2.5 X 1.6 X 10^-19J
Maximum Wavelength, λ0 = \(\frac{hc}{\Phi_0} \) = 4.98 X 10^-7 m
λ0 = 4980 Å.