Right option is (b) 714 m/s
For explanation: Mass of one Oxygen molecule = 32 g/mol
= 32 X 10^-3/6.022 X 10^23
= 5.31 X 10^-26 Kg
Now,\(V_p = \sqrt{\frac{2kT}{M}}\)
Here, T = 300 K, k = 1.98 X 10^23 and M = 32
Therefore, \(V_p = \sqrt{\frac{2X 1.98X 30}{5.31}} \) X 10^4
= 714 m/s.