Right option is (c) 0 K
To elaborate: We know that the Fermi-Dirac distribution is given by:
FFD(E) = \( \frac{1}{e\frac{E-E_F}{nT}+1}\)
For all the quantum states with energy greater than Fermi energy to be empty,
FFD(E) = 0, for E > EF and FFD(E) = 1, for E < EF
Therefore, for E < EF \( \frac{1}{e\frac{E-E_F}{nT}+1}=1\)
\(e\frac{E-E_F}{nT}= 0\)
As, E < EF, E- EF < 0. Therefore, to satisfy the given statement,
T = 0 K
Thus, we can define Fermi energy as the energy of the uppermost occupied level at 0 K.