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Arrange the slabs in the increasing order of the refractive index.

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Arrange the slabs in the increasing order of the refractive index.

(a) A > B > C

(b) B > A > C

(c) C > A > B

(d) C > B > A

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I want to ask this question from Velocity of Light topic in chapter Optics of Engineering Physics II

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The correct option is (c) C > A > B

For explanation: As we know, the ray bends towards the normal if the medium is optically denser. Hence, by observing the shift in the direction of incident light between A and B, we realize that the refractive index of A is greater than B. Similarly, R.I of C is greater than A and B. Thus, the right order is C > A > B.

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