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According to stoke’s law, the expression for maxima is: 2μtcosr = ____________

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According to stoke’s law, the expression for maxima is: 2μtcosr = ____________

(a) nλ

(b) 2nλ

(c) (2n + 1) λ/2

(d) (n + 1) λ/2

I got this question by my college director while I was bunking the class.

This intriguing question comes from Interference of Light in section Interference of Engineering Physics II

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The correct option is (c) (2n + 1) λ/2

Best explanation: Stoke’s relation states that when a light ray is incident on the interface of the optically denser medium, then the reflected wave suffers a phase change of π. Thus, for maxima 2μtcosr = (2n + 1) λ/2 and for minima 2μtcosr = nλ.

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