Correct option is (c) 15000
Easy explanation: We know; the dispersive power of a grating is given by:
\(\frac{\partial \theta}{\partial \lambda}\) = n/(a + b) cosθ
Now, here n = 3 and a + b = 1/5000 cm
Here, sinθ = nλ/(a + b) = 0.6
cosθ = 0.8
Now, \(\frac{\partial \theta}{\partial \lambda}\) = 3 X 4000/0.8
= 15000.