Right option is (a) 2λ
Explanation: For a half-wave plate, t = \(\frac{\lambda}{2(\mu_E-\mu_0)}\)
Multiplying numerator and denominator with 2 we get, t = \(\frac{2\lambda}{4(\mu_E-\mu_0)}\)
As we can see, this resembles the expression for thickness of a quarter-wave plate, t = \(\frac{2\lambda}{4(\mu_E-\mu_0)}\). Thus, for λ’ = 2 λ, a half wave plate would behave as a quarter-wave plate.