Right choice is (c) 3.57 X 10^6 Wm^-2
Best explanation: Area of the image = \(\frac{\pi\lambda^2f^2}{a^2}\)
λ = 5000 Å = 5.0 X 10^-7m, f = 0.2 m
a = 1.5/2 cm = 0.75 X 10^-2 m
Putting in the formula we get, Are = 5.6 X 10^-10 m^2
Intensity = Power/Area
= 2 X 10^-3W/ 5.6 X 10^-10 m^2
= 3.57 X 10^6 Wm^-2.