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The correct expression for Bragg’s law is nλ = ___________

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The correct expression for Bragg’s law is nλ = ___________

(a) dsinθ

(b) dcosθ

(c) 2dsinθ

(d) 2dcosθ

I have been asked this question in examination.

I want to ask this question from Bragg’s Law topic in chapter X-Rays and Compton Effect of Engineering Physics II

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The correct option is (c) 2dsinθ

The explanation is: Bragg’s law gives us the relation between the wavelength of the incident X-ray and the angle of incidence. The expression is: nλ = 2dsinθ.

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