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If Ie is the current entering the emitter, Ib is the current leaving the base and Ic is the current leaving the collector in a p-n-p transistor used for amplification, what is the relation between Ie, Ib and Ic?

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If Ie is the current entering the emitter, Ib is the current leaving the base and Ic is the current leaving the collector in a p-n-p transistor used for amplification, what is the relation between Ie, Ib and Ic?

(a) Ie < Ic

(b) Ic < Ib

(c) Ib < Ic

(d) Ie < Ib + Ic

The question was asked in an interview.

This key question is from Transistors topic in division Semiconductors of Engineering Physics II

1 Answer

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Best answer
Right option is (c) Ib < Ic

Easiest explanation: The total current entering the emitter, Ie, goes to the base form where most of the current enters the collector and a very small fraction of the current leaves the base. Thus, Ib < Ic.

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