Question

If the magnetic meridian of a certain place, the horizontal component of the earth’s magnetic field is 0.26 G and the dip angle is 60°, what is the magnetic field of earth at this location?

(a) 0.52 G

(b) 0.46 G

(c) 0.78 G

(d) 0.94 G

This question was posed to me in a job interview.

I would like to ask this question from Parameters topic in section Magnetic Properties of Materials of Engineering Physics II

Answer 1

The correct option is (a) 0.52 G

Explanation: It is given that, HE = 0.26 G. Thus, we have

cos60° = HE/BE

BE = HE/ cos60°

= 0.26 X 2

= 0.52 G.