Question

Calculate the de-Broglie wavelength of an electron which has been accelerated from rest on application of potential of 400volts.

(a) 0.1653 Amstrong

(b) 0.5125 Amstrong

(c) 0.6135 Amstrong

(d) 0.2514 Amstrong

I had been asked this question in my homework.

This interesting question is from Dimensions of a Physical Quantity in portion Advanced Engineering Materials of Engineering Physics II

Answer 1

The correct option is (c) 0.6135 Amstrong

To explain I would say: de-Broglie wavelength = h/√(2×m×e×V)

De-Broglie wavelength = (6.625×10^(-14))/√(2×9.11×10^(-31)×1.6×10^(-19)×400)

Wavelength = 0.6135 Amstrong.