Question

In the 8089 architecture, the address of memory table for channel-2 is calculated by

(a) adding 16 to the contents of CCP

(b) adding 8 to the contents of CCP

(c) adding memory table address of channel-1

(d) none of the mentioned

I have been asked this question in a job interview.

Question is taken from I/O Processor 8089 topic in section Multimicroprocessor Systems of Microprocessor

Answer 1

The correct choice is (b) adding 8 to the contents of CCP

To explain: The address of the memory table for channel-2 is calculated by adding 8 to the contents of CCP or by adding memory table address for channel-1 to the contents of CCP.