Question

A single phase full bridge inverter circuit, has load R = 2 Ω and dc source Vs = 230 V. Find the value of power delivered to the load in watts only due to the fundamental component of the load current.

(a) 5361.5 W

(b) 2142.5 W

(c) 21424.5 W

(d) 214.2 W

The question was posed to me in a job interview.

The question is from Single Phase VSI-4 topic in division Inverters of Power Electronics

Answer 1

Right option is (c) 21424.5 W

The explanation is: The fundamental component of voltage = (4Vs/π) sinωt

Peak value Vm = 4Vs/π

Rms voltage = 4Vs/π√2 = 207 V

RMS Current (Irms) = 207/2 = 103.5 A

P = (Irms)^2 x R = 21424.5 W.