Question

The total thermal resistance between junction and ambient θjA is 10°C/W. θjc is 2°C/W. θcs is 4°C/W. θsA = ?

(a) 4°C/W

(b) 2°C/W

(c) 10°C/W

(d) 16°C/W

I have been asked this question during an interview for a job.

This question is from Thyristor Mounting topic in section Power Electronics Devices of Power Electronics

Answer 1

Correct option is (a) 4°C/W

To explain I would say: θjA = θjc+ θcs+ θsA.