A circuit is so formed such that the source-R-C-diode-switch are in series. Consider the initial voltage across the C to be zero. The diode is so connected that it is forward biased when the switch is closed. When the switch is closed,

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A circuit is so formed such that the source-R-C-diode-switch are in series. Consider the initial voltage across the C to be zero. The diode is so connected that it is forward biased when the switch is closed. When the switch is closed,

asked Sep 27, 2022 in Power Electronics by Theta (27.1k points)

A circuit is so formed such that the source-R-C-diode-switch are in series. Consider the initial voltage across the C to be zero. The diode is so connected that it is forward biased when the switch is closed. When the switch is closed,

(a) the current will decay exponentially & the voltage will increase exponentially

(b) the current will increase exponentially & the voltage will increase exponentially

(c) the current will fall to zero & the voltage both will decay exponentially

(d) the voltage and current both remain constant

This question was posed to me by my school principal while I was bunking the class.

My query is from Diode Circuits-1 topic in chapter Diode Circuits of Power Electronics

1 Answer

hutan · Answer 1 · 2022-10-07T19:21:30+0000

Correct answer is (a) the current will decay exponentially & the voltage will increase exponentially

The best I can explain: Instant switch is closed, the current is maximum Vs/R than starts to reduce, whereas voltage starts to increase from 0 to Vs (Capacitor Charging).

A circuit is so formed such that the source-R-C-diode-switch are in series. Consider the initial voltage across the C to be zero. The diode is so connected that it is forward biased when the switch is closed. When the switch is closed,

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