Question

For the below shown converter configuration, find the expression for the average value of voltage across the resister R with Vs = Vm sinωt and firing angle = α.

(a) Vm/π cosα

(b) 2Vm/π cosα

(c) Vm/π (1+cosα)

(d) 2Vm/π (1+cosα)

I had been asked this question in semester exam.

This interesting question is from Single Phase FW AC-DC-4 in division Converters of Power Electronics

Answer 1

The correct choice is (c) Vm/π (1+cosα)

For explanation I would say: Vo = Vo = 1/π x [∫ Vm sinωt d(ωt)] where the integration would run from α to π.