Question

For the below given circuit with firing angle α & angular frequency of ω, the circuit turn-off time in secs can be given by

(a) α/π

(b) π/α

(c) ω/π

(d) π/ω

I got this question at a job interview.

I need to ask this question from Single-Phase HW AC-DC-1 in section Converters of Power Electronics

Answer 1

The correct option is (d) π/ω

For explanation I would say: The circuit turns of at ωt = π as it is a half wave circuit.

Hence toff = π/ω.