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For a step-up/step-down chopper, if current increases from I1 to I2 linearly during Ton, then find the energy stored in the inductor during Ton

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For a step-up/step-down chopper, if current increases from I1 to I2 linearly during Ton, then find the energy stored in the inductor during Ton

(a) zero

(b) Vs x (I1 + I2)

(c) Vs x [ (I1 + I2)/2 ] x Ton

(d) Vs x [ (I1 + I2)/2 ] x T

I had been asked this question during an interview.

This intriguing question comes from Choppers-5 topic in division Choppers of Power Electronics

1 Answer

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by (45.1k points)
The correct answer is (c) Vs x [ (I1 + I2)/2 ] x Ton

The explanation: Iavg =  [ (I1 + I2)/2 ]

Energy stored = Win = Vs x [ (I1 + I2)/2 ] x Ton.

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