Question

In case of a single-phase half-wave circuit with RL load, with firing angle α and extinction angle β, the conduction angle γ can be written as

(a) γ = β+α

(b) γ = β-α

(c) γ = β/α

(d) γ = α/β

I have been asked this question in unit test.

I would like to ask this question from Single-Phase HW AC-DC-2 topic in section Converters of Power Electronics

Answer 1

Right option is (b) γ = β-α

For explanation I would say: Extinction angle is some angle > π at which load current reduces to zero. It depends upon the inductor value.