The correct option is (c) Vs/(1-α)
Easiest explanation: During Ton, the energy stored in the inductor is
Win = Vs x Ton x (I1+I2)/2
During Toff, the energy released by the inductor is
Wout = (Vo – Vs) x Toff x (I1+I2)/2
Considering ideal condition,
Win = Wout
Vo = Vs x (T/Toff)
α = Ton/T
Vo = T/T-Ton = Vs/1-α.