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In case of a single-pulse width modulation with the pulse width = 2d, to eliminate the 5th harmonic from the output voltage waveform, the value of the pulse width (2d) must be equal to

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In case of a single-pulse width modulation with the pulse width = 2d, to eliminate the 5th harmonic from the output voltage waveform, the value of the pulse width (2d) must be equal to

(a) 72°

(b) 86°

(c) 91°

(d) 5°

The question was posed to me during an interview.

My question is from PWM Inverters-2 topic in division Inverters of Power Electronics

1 Answer

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by (45.1k points)
Right choice is (c) 91°

To explain: To eliminate the nth harmonic, nd = π.

Therefore, d = π/n = π/5 = 36°

Hence, 2d = 72°.

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