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A single-phase bridge inverter, fed from a 230 V dc is connected to the load R = 10 Ω and L = 0.03 H. The output is a quasi-square wave with an on period of 0.5 of a cycle. Determine the fundamental component of rms output voltage.

(a) 207.10 V

(b) 146.42 V

(c) 265.4 V

(d) 129 V

This question was posed to me by my college professor while I was bunking the class.

I want to ask this question from PWM Inverters-5 in portion Inverters of Power Electronics

1 Answer

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by (45.1k points)
The correct choice is (b) 146.42 V

To explain I would say: For quai-square wave or single-pulse width modulated wave pulse width 2d = 0.5 x 180° = 90° or d = 45°

Hence, Vo1 = (4Vs/π√2) sind = (4 x 230)/( π.√2) sin45° = 146.423 V.

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