Question

What is the integration property of the continuous time fourier series?

(a) y(t) ↔ Yn = 1/jnwXn

(b) y(t) ↔ Yn = 1/jwXn

(c) y(t) ↔ Yn = 1/jnXn

(d) y(t) ↔ Yn = 1/jnw

This question was posed to me during an interview for a job.

My question is based upon Fourier Series Properties topic in division Fourier Series of Signals and Systems

Answer 1

Right option is (a) y(t) ↔ Yn = 1/jnwXn

Easy explanation: y(t)↔ Yn = 1/jnwXn, here x(t) is the signal and y(t) is the output.

This is the integration property of the signal.