The correct choice is (c) \(\frac{1}{2+jω}\)
Easy explanation: Impulse response h (t) = e^-2t u (t)
Taking Fourier transform, H (ω) = \(\int_{-∞}^∞ e^{-2t} \,u(t) e^{-jωt} \,dt\)
= \(\int_0^∞ e^{-2t} e^{-jωt} \,dt\)
= \(\int_0^∞ e^{-(2+jω)t} \,dt\)
= \(\frac{1}{2+jω}\).