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For any given signal, average power in its 6 harmonic components as 10 mW each and fundamental component also has 10 mV power. Then, average power in the periodic signal is _______________

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in Signals and Systems by (1.2m points)
For any given signal, average power in its 6 harmonic components as 10 mW each and fundamental component also has 10 mV power. Then, average power in the periodic signal is _______________

(a) 70

(b) 60

(c) 10

(d) 5

I got this question in an online quiz.

This intriguing question originated from Power and Energy Signals topic in portion Fourier Series of Signals and Systems

1 Answer

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by (42.1k points)
The correct choice is (b) 60

Easiest explanation: We know that according to Parseval’s relation, average power is equal to the sum of the average powers in all of its harmonic components.

∴ Pavg = 10 × 6 = 60.

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