# A current I given by I = – 8 + 6$\sqrt{2}$ (sin (ωt + 30°)) A is passed through three meters. The respective readings (in ampere) will be? (a)8, 6 and 10

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A current I given by I = – 8 + 6$\sqrt{2}$ (sin (ωt + 30°)) A is passed through three meters. The respective readings (in ampere) will be?

(a) 8, 6 and 10

(b) 8, 6 and 8

(c) – 8, 10 and 10

(d) -8, 2 and 2

I have been asked this question in a national level competition.

I need to ask this question from Properties of ROC in chapter Laplace Transform and System Design of Signals and Systems

by (42.1k points)
Right answer is (c) – 8, 10 and 10

Explanation: PMMC instrument reads only DC value and since it is a center zero type, so it will give – 8 values.

So, rms = $\sqrt{8^2 + (\frac{6\sqrt{2}}{\sqrt{2}})^2}$  = 10 A

Moving iron also reads rms value, so its reading will also be 10 A.

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