Correct option is (c) 3225.8 kHz
Easy explanation: We know that, F = \(\frac{1}{2π×(R_1×R_2)×(C_1×C_2)}\)
Where, R1 = 4700 Ω, R2 = 4700 Ω, C1 = 0.047×10^-6 F, C2 = 0.047 × 10^-6 F
∴ F = \(\frac{1}{2π×(4700×4700)×(C_1×C_2)}\)
= \(\frac{1}{2π×48796.81×10^{-12}}\)
= \(\frac{10^6}{2π×0.04879681}\)
= \(\frac{10^6}{0.30654156042}\) = 3225.8 kHz.