The correct answer is (a) syms t; laplace(t/t)
The explanation: The laplace command won’t understand 1 is a unit function. Also, if we don’t define t as symbolic, it won’t be able to understand ‘t/t’. Finally, sym t doesn’t properly define t for using it in the laplace command so we need to write t=sym(‘t’) while using the sym command. Instead of this, we write syms t to define it, as a symbolic variable, for the laplace command.