Question

A 25 Ω resistor has a voltage of 150 sin377 t. Find the corresponding power.

(a) 900 sin^2 337 t

(b) 90 sin^2 337 t

(c) 900 sin^2 377 t

(d) 9 sin^2 337 t

This question was posed to me by my college professor while I was bunking the class.

This interesting question is from Basic Network Concepts topic in section Circuit Elements and Kirchhoff’s Laws of Network Theory

Answer 1

Right answer is (c) 900 sin^2 377 t

The explanation: Given R = 25 Ω and v = 150 sin 377 t

i = \(\frac{v}{R} = \frac{150 sin⁡ 377 t}{25}\) = 6 sin 377 t

p = vi = (150 sin 377 t)(6 sin 377 t) = 900 sin^2 377 t.