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If the resistances 3Ω, 5Ω, 7Ω, 9Ω are in series, then their equivalent resistance(Ω) is?

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If the resistances 3Ω, 5Ω, 7Ω, 9Ω are in series, then their equivalent resistance(Ω) is?

(a) 9

(b) 20

(c) 24

(d) 32

I have been asked this question in final exam.

This intriguing question originated from Circuit Elements and Kirchhoff’s Laws in division Circuit Elements and Kirchhoff’s Laws of Network Theory

1 Answer

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Correct answer is (c) 24

Easy explanation: If the resistances are in series, then equivalent resistance is the sum of all the resistances that are in series. Equivalent resistance is (3+5+7+9)Ω = 24Ω.

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