Question

Determine the current in all resistors in the circuit shown below.

(a) 2A, 4A, 11A

(b) 5A, 4.8A, 9.6A

(c) 9.3A, 20.22A, 11A

(d) 10.56A, 24.65A, 14.79A

This question was posed to me in a national level competition.

This key question is from Kirchhoff’s Current Law in chapter Circuit Elements and Kirchhoff’s Laws of Network Theory

Answer 1

Right option is (d) 10.56A, 24.65A, 14.79A

Best explanation: All the resistors are in parallel, so the voltage across each resistor is the same V.

i1=V/7, i2 = V/3, i3=V/5. By current law, 50A = V/7 + V/3 + V/5. On solving, we obtain V and then values of i1, i2, i3.