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While computing the Norton equivalent resistance and the Norton equivalent current, which of the following steps are undertaken?

(a) Both the dependent and independent voltage sources are short-circuited and both the dependent and independent current sources are open-circuited

(b) Both the dependent and independent voltage sources are open-circuited and both the dependent and independent current sources are short-circuited

(c) The dependent voltage source is open-circuited keeping the independent voltage source untouched and the dependent current source is short-circuited keeping the independent current source untouched

(d) The dependent voltage source is short-circuited keeping the independent voltage source untouched and the dependent current source is open-circuited keeping the independent current source untouched

I had been asked this question in unit test.

This key question is from Norton’s Theorem Involving Dependent and Independent Sources in division Useful Theorems in Circuit Analysis of Network Theory

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The correct option is (d) The dependent voltage source is short-circuited keeping the independent voltage source untouched and the dependent current source is open-circuited keeping the independent current source untouched

Best explanation: While computing the Norton equivalent voltage consisting of both dependent and independent sources, we first find the equivalent resistance called the Norton resistance by opening the two terminals. Then while computing the Norton current, we short-circuit the dependent voltage sources keeping the independent voltage sources untouched and open-circuiting the dependent current sources keeping the independent current sources untouched.

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