The correct option is (c) -1.393 V
The best explanation: The datum node is the lower branch.
By superposition, the current i is given by, i = 2 \(\frac{7}{15+5+7} + \frac{3}{15+5+7} + 4I \frac{7+15}{15+5+7}\)
Or, I = \(\frac{17}{27} + \frac{88}{27I}\)
∴ The solution for i yields, I = \(\frac{\frac{17}{27}}{1 – \frac{88}{27}} = -\frac{17}{61}\) A
∴ V2 = 5I = -1.393 V.