Question

In the circuit shown below, find voltage across inductive reactance.

(a) 9.5

(b) 10

(c) 9

(d) 10.5

I had been asked this question by my college director while I was bunking the class.

This interesting question is from Series Circuits in section Complex Impedence of Network Theory

Answer 1

Right option is (a) 9.5

Explanation: Voltage across inductor = IXL. The values of I = 3.03 mA and XL = 10000Ω. On substituting the values in the equation, the voltage across inductor = 3.03×10^-3×1000 = 9.51V.