The correct option is (b) 26∠20.5⁰
To explain: First the inductive reactance is calculated. XL=6.28 x 50 x 0.1 = 31.42Ω. In figure the 10Ω resistance is in series with the parallel combination of 20Ω and j31.42Ω. ZT = 10 + (20)(j31.42)/(20+j31.42)=24.23+j9.06=25.87∠20.5⁰.