Question

Find Z31, Z32, Z33 in the circuit shown below.

(a) 0Ω, j6Ω, (4-j6) Ω

(b) 0Ω, -j6Ω, (4+j6) Ω

(c) 0Ω, -j6Ω, (4-j6) Ω

(d) 0Ω, j6Ω, (4+j6) Ω

This question was addressed to me in an interview for internship.

I would like to ask this question from Mesh Analysis topic in division Steady State AC Analysis of Network Theory

Answer 1

The correct answer is (a) 0Ω, j6Ω, (4-j6) Ω

The best I can explain: Z31 = common impedance to loop 3 and loop 1 = 0 Ω. Z32 = common impedance between loop3 and loop 2 = – (-j6) Ω. Z33 = self impedance of loop 3 = (4-j6) Ω.