Question

Find the voltage across (2+j5) Ω impedance using Superposition theorem.

(a) 40.85∠72.53⁰

(b) 40.85∠-72.53⁰

(c) 41.85∠72.53⁰

(d) 41.85∠-72.53⁰

The question was asked during an online exam.

This intriguing question originated from Superposition Theorem in division Steady State AC Analysis of Network Theory

Answer 1

The correct option is (a) 40.85∠72.53⁰

Explanation: The voltage across (2+j5) Ω impedance using Superposition theorem is the sum of the voltages V1 and V2. V = V1+V2 = 29.16∠-9.28^o+46.69∠110.72^o=40.85∠72.53^o V.